Is The Formal Charge On N The Same Or Different In These Two Species? Is The Formal Charge On The Same (2024)

Answer:

Abrasion I think

Explanation:

Answer:

[tex]\Delta S=51.1\frac{J}{K}[/tex]

Explanation:

Hello!

In this case, since the entropy and enthalpy are related via the following equation for any process:

[tex]\Delta S=\frac{m\Delta H}{T}[/tex]

As this problem relates the enthalpy and entropy of fusion, given the mass, melting temperature and heat of fusion, we compute the change in entropy of fusion as shown below:

[tex]\Delta S=\frac{0.0419kg*333,000\frac{J}{kg} }{273.15K}\\\\\Delta S=51.1\frac{J}{K}[/tex]

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use n = m / M to find the moles

once you have the moles you will be able to find the Volume wirh the formula n × Vm

Vm is always 22,4 dm³/mol

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Answer:

A, B, C, D, and A

Explanation:

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Nitrogen tribromide is a chemical compound with the formula NBr3. It is extremely ... NBr3 was first prepared by reaction of bistrimethlysilylbromamine (bis(trimethylsilyl) amine bromide) ..

Answer:

119.60 moles

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

[tex]n = \frac{N}{L} \\[/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

[tex]n = \frac{7.2 \times {10}^{25} }{6.02 \times {10}^{23} } \\ =119.60132...[/tex]

We have the final answer as

119.60 moles

Hope this helps you

First question: The number of electrons surrounding the central atom in a stable molecule is fewer than eight. For example, Boron only needs 6 electrons.

Second question: There are a number of molecules whose total number of valence electrons is an odd number. It is not possible for all of the atoms in such a molecule to satisfy the octet rule. An example is nitrogen dioxide (NO2). Each oxygen atom contributes six valence electrons and the nitrogen atom contributes five for a total of seventeen.

Third question: Expanded octet occurs when an atom is able to have more than 8 valence electrons. For example, in SO₃, the sulfur atom forms 6 covalent bonds, hence it has 12 valence electrons. Expansion of octet is possible only from Period 3 elements onwards, due to the presence of low-lying empty d orbitals that can accommodate the extra electrons.

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Answer:

Incomplete Octet

In some compounds, the number of electrons surrounding the central atom in a stable molecule is fewer than eight. Beryllium is an alkaline earth metal and so may be expected to form ionic bonds. However, its very small size and somewhat higher ionization energy compared to other metals actually lead to beryllium forming primarily molecular compounds. Since beryllium only has two valence electrons, it does not typically attain an octet through sharing of electrons. The Lewis structure of gaseous beryllium hydride (BeH 2 ) consists of two single covalent bonds between Be and H

Odd-Electron Molecules

There are a number of molecules whose total number of valence electrons is an odd number. It is not possible for all of the atoms in such a molecule to satisfy the octet rule. An example is nitrogen dioxide (NO 2 ). Each oxygen atom contributes six valence electrons and the nitrogen atom contributes five for a total of seventeen.

Expanded Octets

Atoms of the second period cannot have more than eight valence electrons around the central atom. However, atoms of the third period and beyond are capable of exceeding the octet rule by having more than eight electrons around the central atom. Starting with the third period, the d sublevel becomes available, so it is possible to use these orbitals in bonding, resulting in an expanded octet.

Phosphorus and sulfur are two elements that react with halogen elements and make stable compounds with expanded octets. In phosphorus pentachloride, the central phosphorus atom makes five single bonds to chlorine atoms and as a result has ten electrons surrounding it

Explanation:

Answer:

physical change

Explanation:

Physical changes alter only the size, shape, form or matter state of a material. Water boiling, melting ice, tearing paper, freezing water and crushing a can are all examples of physical changes. On the other hand, chemical changes are a bit different. In a chemical change, a new substance is formed.

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Answer:

the answer is distillate

Answer:

The general principle behind Slater's Rule is that the actual charge felt by an electron is equal to what you'd expect the charge to be from a certain number of protons, but minus a certain amount of charge from other electrons. Slater's rules allow you to estimate the effective nuclear charge Zeff from the real number of protons in the nucleus and the effective shielding of electrons in each orbital "shell" (e.g., to compare the effective nuclear charge and shielding 3d and 4s in transition metals). Slater's rules are fairly simple and produce fairly accurate predictions of things like the electron configurations and ionization energies.

Explanation:

The shielding constant of a d electron in copper is 22.15.

From Slaters's rule;

Zeff = Z - S

Where;

Z = Nuclear charge

S = Shielding constant

Now we are required to find the shielding constant for copper d - electrons;

The shielding contributed by the d electrons = (9 × 0.35) = 3.15

The shielding contributed by other electrons = (19 × 1.00) = 19

Total shielding constant = 3.15 + 19 = 22.15

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Answer:

Yes.

Explanation:

Mold is a living organism. All living organisms are made up of cells.

Answer:

2.1 atm

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we are finding the new pressure

[tex]P_2 = \frac{P_1V_1}{V_2} \\[/tex]

From the question we have

[tex]P_2 = \frac{3.5 \times1.2 }{2} = \frac{4.2}{2} \\ [/tex]

We have the final answer as

2.1 atm

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Answer:

increasing the separation distance between objects decreases the force of attraction

Explanation:

Answer:

B

Explanation:

The atomic number or proton number (symbol Z) of a chemical element is the number of protons found in the nucleus of every atom of that element.

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Answer:

C or you big S U S.

Explanation:

Answer:gas formation

2 products formed

Decomposition

Dioxide

Explanation:

Edge 2021

Answer: person above is correct and deserves Brainly

Explanation:

Answer:

41.3 s

Explanation:

Let t₁ represent the time taken for SO₂ to effuse.

Let t₂ represent the time taken for Ar to effuse.

Let M₁ represent the molar mass of SO₂

Let M₂ represent the molar mass of Ar

From the question given above,

Time taken (t₁) for SO₂ = 52.3 s

Time taken (t₂) for Ar =?

Molar mass (M₁) of SO₂ = 32 + (16×2) = 32 + 32 = 64 g/mol

Molar mass (M₂) of Ar = 40 g/mol

Finally, we shall determine the time taken for Ar to effuse by using the Graham's law equation as shown below:

t₂ / t₁ = √(M₂ / M₁)

t₂ / 52.3 = √(40 / 64)

t₂ / 52.3 = √0.625

t₂ / 52.3 = 0.79

Cross multiply

t₂ = 52.3 × 0.79

t₂ = 41.3 s

Thus, the time taken for the amount of Ar to effuse is 41.3 s

Answer:

i think it is radiation if not its conduction.

Answer:

Conduction

Explanation:

Conduction is the process by which heat or electricity is directly transmitted through a substance when there is a difference of temperature or of electrical potential between adjoining regions, without movement of the material. When a pot of water is placed on the stove to boil, conduction heat warms up the pot, which then heats the water molecules inside.

Answer:

The correct answer is 169.56 g/mol.

Explanation:

Based on the given information, the mass of Ag deposited is 1.24 g, and the mass of unknown metal X deposited in another cell is 0.650 g. The number of moles of electrons can be determined as,

= 1.24 g Ag * 1mol Ag/107.87 g/mol Ag * 1 mol electron/1 mol Ag ( the molecular mass of Ag is 107.87 g/mol)

= 0.0115 mole of electron

The half cell reaction for the metal X is,

X^3+ (aq) + 3e- = X (s)

From the reaction, it came out that 3 faraday will reduce one mole of X^3+.

The molar mass of X will be,

= 0.650 g/0.0115 *3 mol electron/1 mol

= 56.52 * 3

= 169.56 g/mol

Answer:

C. There are four sp3 hybrid orbital.

Answer: A, metals tend to have lower ionization energies than nonmetals

Explanation:

Got it right on the quiz

Answer:

b. number of protons

Explanation:

The definition of the atomic number is the number of protons.

It is possible for two atoms to have the same mass number but a different number of protons (for example one atom with 23 protons and 25 neutrons, and one atom with 24 protons and 24 neutrons). This is because the mass number is equal to the sum of the number of protons and neutrons.

Answer:

0.321M would be the concentration of the final solution

Explanation:

In the problem, you are decreasing the concentration of a solution (The stock solution) by the addition of more solvent (This process is known as dilution).

You are increasing the volume of the solution from 15mL to 700mL, that means the solution is diluted:

700mL / 15mL = 46.67 times

Now, to know the concentration of a final solution we need to take the concentration of the stock solution. Assuming the stock solution is 15M:

15M / 46.67 =

0.321M would be the concentration of the final solution

Answer:

[tex]d.) \: E = hf[/tex]

Explanation:

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Answer:

Concept: Advanced Chemisty Analysis

If the element y has two naturally occurring isotopes, then the relative abundance is going to be close to the average of both of those isotopes

Explanation:

The temperature which a given solid will melt

Answer:

the temperature at which a given solid will melt.

Explanation:

I don't know how to Explain it. (lol)

Answer:

[tex]Y=85\%[/tex]

Explanation:

Hello!

In this case, since we know the balanced chemical reaction, we are first able to realize there is a 1:3 mole ratio between zinc phosphate and zinc chloride; it means that we can first compute the moles of the desired product via stoichiometry:

[tex]n_{ZnCl_2}=20gZn_3(PO_4)_2*\frac{1molZn_3(PO_4)_2}{386.11gZn_3(PO_4)_2}*\frac{3molZnCl_2}{1molZn_3(PO_4)_2}=0.16gZnCl_2[/tex]

Next, since those moles are associated with the theoretical yield of zinc chloride, we obtain the corresponding mass:

[tex]m_{ZnCl_2}^{theoretical}=0.16molZnCl_2*\frac{136.29gZnCl_2}{1molZnCl_2} =21gZnCl_2[/tex]

Finally, we compute the percent yield by diving the actual yield (18 g) by the theoretical yield:

[tex]Y=\frac{18g}{21g}*100\%\\\\Y=85\%[/tex]

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Answer:

b. 295 pm

Explanation:

To answer this question we need to use the equation of a face-centered cubic laticce:

Edge length = √8 R

Where R is radius of the atom.

Replacing:

417pm = √8 R

R = 147.4pm is the radius of the atom

As diameter = 2 radius.

Diameter of the metal atom is:

147.4pm* 2 =

295pm

Right answer is:

b. 295 pm